Calculate the binding energy per nucleon of 
nucleus.
[Given : m( 
) = 39.962589 u, M n (mass of a neutron) = 1.008665 u, M p (mass of a proton) = 1.007825 u]
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
Sol. Number of protons in the nucleus of 
= 20
Number of neutrons in the nucleus of 
= 20
Mass of 20 protons = 20 × 1.007825u
= 20.1565u
Mass of 20 neutrons = 20 × 1.008665u
= 20.1733u
∴ Total mass = 20.1565 u + 20.1733u
= 40.3298 u
Mass of 
nucleus = 39.962589u
Mass defect Δ m = 40.3298u – 39.962589u
= 0.367211 u
Binding energy = 0.367211 × 931 MeV
= 341.87 MeV
∴ Binding energy per nucleon = 
MeV
= 8.547 MeV
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